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Muhlenberg College Allentown, Pa. |
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Tuesday, November 9, 2004 |
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Mules Now in Top 3 in Four Defensive Categories
In spite of its fourth-quarter loss at McDaniel on Saturday, the Muhlenberg football team is still alive for an NCAA Tournament berth. The Mules need the following six things to happen all feasible this week in order to earn the Centennial Conferences automatic bid to the NCAAs for the third year in a row:
1. Muhlenberg (7-2, 4-2 CC) defeats Moravian (7-2) Items 2 through 4 would result in a five-way tie for the CC championship between Muhlenberg, McDaniel, Johns Hopkins, Dickinson and Franklin & Marshall. All the teams would be 4-2 in the league and 2-2 against each other. The next tiebreaker is strength of schedule, and thats where the Upstate New York teams come in. Strength of schedule is determined by an NCAA formula that awards points based on where a game is played and an opponents record. Points change at the winning percentages of .333, .500 and .667. Johns Hopkins win against Rochester would be worth two points fewer if the Yellow Jackets are 4-6 instead of 5-5. Similarly, Muhlenbergs win at Union gains two points if the Dutchmen finish 6-3 rather than 5-4. Those two two-point swings would give Muhlenberg a one-point advantage over Johns Hopkins in the strength-of-schedule calculations, and the automatic bid to the NCAA Tournament. The above is the only scenario that favors the Mules. A three- or four-way tie for the championship gives the automatic bid to either McDaniel or Johns Hopkins, since the tie can be broken without going to strength of schedule. Of course, if McDaniel defeats Johns Hopkins, there is no need for tiebreakers, since the Green Terror would win the title outright. If you are not confused enough already and want a more thorough explanation of strength of schedule, click here. |
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Questions or comments? Send mail to falk@muhlenberg.edu Last updated November 9, 2004 |